sku组合算法性能测试

JavaScript performance comparison

Revision 7 of this test case created by 重启

Preparation code

``````

<script>
Benchmark.prototype.setup = function() {
var saleProp = [
['A', 'B', 'C', 's', 's', 'as', 'ad', 'sas', 'as', 'sa', 'asd', 'asd', 'asd', 'asdf', 'asdf'],
['D', 'E', 'F', 'B', 'C', 's', 's', 'as', 'ad', 'sas', 'as', 'sa', 'asd', 'asd', 'asd', 'asdf', 'asdf'],
['H', 'B', 'C', 's', 's', 'as', 'ad', 'sas', 'as', 'sa', 'asd', 'asd', 'asd', 'asdf', 'asdf'],
['J', 'K', 'L', 'B', 'C', 's', 's', 'as', 'ad', 'sas', 'as', 'sa', 'asd', 'asd', 'asd', 'asdf', 'asdf'],
];
function concatAll(items){
var base = items[0]

return mulit(base, items.slice(1))

function mulit(base, leftArr){
var multiplier = leftArr[0];

var newBase = [];
for(var i = 0, len = base.length; i < len; i++){
var b = base[i];
for(var j = 0, len2 = multiplier.length; j < len2; j++){
var m = multiplier[j];
newBase.push(b+''+m);
}
}

var _left = leftArr.slice(1);
if(_left.length){
return mulit(newBase, _left);
}else{
return newBase;
}
}
}

function concatAll2(arr) {
var funcBody = 'var ret = [];',
IDX = ['i', 'j', 'k', 'l'];

for (var i = 0, len = arr.length; i < len; i++) {
var idx = IDX[i];

funcBody += 'for (var ' + idx + ' = 0;' + idx + '< arr[' + i + '].length;' + idx + '++){';
if (i == len - 1) {
var mash = [];
for (var j = 0; j < arr.length; j++) {
var idx2 = IDX[j]
mash.push('arr[' + j + '][' + idx2 + ']');
}
funcBody += 'ret.push(' + mash.join('+') + ')';
}
}

for (var i = 0, len = arr.length; i < len; i++) {
funcBody += '}';
}

funcBody += 'return ret;'

return (new Function('arr', funcBody)(arr));
}

function concatAll3(data){//by chongqi
var item ,idx= -1,
total=1,
//±ê¼Ç×îºóÒ»¸öµÄÊý×é
length = data.length,
lenarr = [],
nowidx = [],

retval = [];
while ( item = data[++idx] ) {
total *= item.length;
lenarr[idx] = item.length;
nowidx[idx] = 0;
}

while ( total-- ) {
var rv = '',arr,
last,i  = 0;

while( i< length ){
rv += data[i++][0];
}
retval.push(rv);

i = nowidx.length;
while( i-- ){
arr = data[ i ];

//arr.push(arr.shift());
last= arr[idx=arr.length-1];
arr[idx] = arr[0];
arr[0] = last;
if (++nowidx[i]<lenarr[i]){
break;
} else {
nowidx[i] =0;
}
}

}
return retval;
}
};

</script>
``````

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Testing in CCBot 2.0.0 / Other 0.0.0
Test Ops/sec
é€’å½’
``concatAll(saleProp);``
pending…
åŠ¨æ€åˆ›å»ºå‡½æ•°
``concatAll2(saleProp);``
pending…
é‡å¯çš„ç‰ˆæœ¬
``concatAll3(saleProp);``
pending…

Revisions

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